javascript 判断两个日期大小

/**
* 检测两个日期的大小
* by www.jiaochengji.com
*/

function(value, element) {
 var productStartTime = document.getElementById("productStartTime").value;
 var productEndTime = document.getElementById("productEndTime").value;
 var OneMonth = productStartTime.substring(5, productStartTime.lastIndexOf("-"));
 var OneDay = productStartTime.substring(productStartTime.length,
 productStartTime.lastIndexOf("-") + 1);
 var OneYear = productStartTime.substring(0, productStartTime.indexOf("-"));
 var TwoMonth = productEndTime.substring(5, productEndTime.lastIndexOf("-"));
 var TwoDay = productEndTime.substring(productEndTime.length,
 productEndTime.lastIndexOf("-") + 1);
 var TwoYear = productEndTime.substring(0, productEndTime.indexOf("-"));
 var today = new Date();
 var tMonth = today.getMonth() + 1;
 var tDay = today.getDate();
 var tYear = today.getYear();
 if (Date.parse(OneMonth + "/" + OneDay + "/" + OneYear) > Date
 .parse(TwoMonth + "/" + TwoDay + "/" + TwoYear)) {
 $("#endTime").focus();
 return false;
 }else{
 return true;
 }
 }